|
现有测试数据如下,要求实现如下图中的效果:
array(4) {
[0] => array(6) {
["visit_id"] => int(127)
["goods_id"] => int(16)
["visittime"] => int(1494399935)
["goods_name"] => string(53) "OPPO R9s 全网通4G+64G 双卡双待手机 玫瑰金"
["shop_price"] => string(6) "500.00"
}
[1] => array(6) {
["visit_id"] => int(124)
["goods_id"] => int(13)
["visittime"] => int(1494399921)
["goods_name"] => string(76) "SIEMENS/西门子 KA92NV09TI双开门家用对开门电冰箱变频旗舰款"
["shop_price"] => string(7) "4000.00"
}
[2] => array(6) {
["visit_id"] => int(123)
["goods_id"] => int(27)
["visittime"] => int(1494399903)
["goods_name"] => string(85) "爱他美白金版Aptamil 幼儿配方奶粉3段(12-36个月适用)900g(欧洲进口)"
["shop_price"] => string(6) "329.00"
}
[3] => array(6) {
["visit_id"] => int(120)
["goods_id"] => int(26)
["visittime"] => int(1494224263)
["goods_name"] => string(21) "欢乐谷免票一张"
["shop_price"] => string(5) "50.00"
}
}
还没实现之前我想这个代码不知道要O(n)呢还是更高的复杂度才能实现,细想一下,其实php的数组底层就是哈希实现的,如何简单利用这个特性使复杂度降到O(1)呢?
show me the code:
/* 浏览记录按日期分组 */
function groupVisit($visit)
{
$curyear = date('Y');
$visit_list = [];
foreach ($visit as $v) {
if ($curyear == date('Y', $v['visittime'])) {
$date = date('m月d日', $v['visittime']);
} else {
$date = date('Y年m月d日', $v['visittime']);
}
$visit_list[$date][] = $v;
}
return $visit_list;
}
说明:入参 $visit 就是上面一开始的测试数据,函数中还对用户体验做了一些优化,比如,你的浏览记录中总是显示出今年的年份,是不是感觉有点冗余,所以如果是本年份的话,年份就要隐藏起来,其他年份还是照样显示出来。不然代码会更加简洁。
好了上面的测试数据经过该函数之后,再把返回值打印出来,有:
array(2) {
["05月10日"] => array(3) {
[0] => array(6) {
["visit_id"] => int(127)
["goods_id"] => int(16)
["visittime"] => int(1494399935)
["goods_name"] => string(53) "OPPO R9s 全网通4G+64G 双卡双待手机 玫瑰金"
["shop_price"] => string(6) "500.00"
}
[1] => array(6) {
["visit_id"] => int(124)
["goods_id"] => int(13)
["visittime"] => int(1494399921)
["goods_name"] => string(76) "SIEMENS/西门子 KA92NV09TI双开门家用对开门电冰箱变频旗舰款"
["shop_price"] => string(7) "4000.00"
}
[2] => array(6) {
["visit_id"] => int(123)
["goods_id"] => int(27)
["visittime"] => int(1494399903)
["goods_name"] => string(85) "爱他美白金版Aptamil 幼儿配方奶粉3段(12-36个月适用)900g(欧洲进口)"
["shop_price"] => string(6) "329.00"
}
}
["05月08日"] => array(1) {
[0] => array(6) {
["visit_id"] => int(120)
["goods_id"] => int(26)
["visittime"] => int(1494224263)
["goods_name"] => string(21) "欢乐谷免票一张"
["shop_price"] => string(5) "50.00"
}
}
}
对的,这正是我想要的效果。
以上所述是小编给大家介绍的PHP 实现浏览记录并按日期分组,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对脚本之家网站的支持!
您可能感兴趣的文章:PHP中获取文件创建日期、修改日期、访问时间的方法php根据年月获取当月天数及日期数组的方法PHP正则匹配日期和时间(时间戳转换)的实例代码PHP获取当前日期及本周一是几月几号的方法关于PHP转换超过2038年日期出错的问题解决PHP判断两个给定日期是否在同一周的方法PHP 实现公历日期与农历日期的互转换
|
|